Question

A diamond falls and breaks into pieces whose weights are in ratio 2:3:5.The value of the diamond is directly proportional to the square of its weights. Find the loss incurred , if the actual cost of the diamond is Rs.96000

Answer 1

suppose  actual weight = W 
and its price would be = kW²         let k = 1 , where k is proportionality constant
                 so price = W²

now it get rubbled into ratio 2 : 3 :  5
let those pieces weigh 2x , 3x and 5x
                     ⇒ 2x+3x+5x = W ⇒  10x = W ⇒ x= W/10

so those pieces gonna weigh = 2W/10 , 3W/10 and 5W/10

and therefore there prices would be = 4W²/100  ,  9W²/100 and 25W²/100

total price = 4W²/100 + 9W²/100  + 25W²/100 = 38W²/100

loss in actual price = W² - 38W²/100 = 62W²/100

percentage loss =  loss/actual price  x 100
                             =(62W²/100) / W²  x 100  = 62%


hope my ans is correct ..............any query then ask.

Answer 2

Answer:

59520

Step-by-step explanation:

Explanation is above...