A diatomic gas does 80 j of work when expanded isobarically.Find the heat given to the gas during the process
Arceus11:
is it 280J
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Given
Work done by Isobaric ( constant pressure )
Process - W 80 J
W = P ∆ V = 80 J from ideal gas equation at constable speed we have
P∆V = nR∆T = ∆T P∆VnR= 80 JnR------- 1
Also Change in internal energy during the process is given by∆U. =nCv∆T=nRγ-1∆TFor diaomic gas, γ=7/5
Putting the value of ∆T from Eq.1 we get∆U=nR75-180 JnR=52×80 J=200 J
From 1st law of thermodynamicsHeat given to gas is given by∆Q=∆U+W⇒∆Q=200 J+80 J=280 J Answer
Work done by Isobaric ( constant pressure )
Process - W 80 J
W = P ∆ V = 80 J from ideal gas equation at constable speed we have
P∆V = nR∆T = ∆T P∆VnR= 80 JnR------- 1
Also Change in internal energy during the process is given by∆U. =nCv∆T=nRγ-1∆TFor diaomic gas, γ=7/5
Putting the value of ∆T from Eq.1 we get∆U=nR75-180 JnR=52×80 J=200 J
From 1st law of thermodynamicsHeat given to gas is given by∆Q=∆U+W⇒∆Q=200 J+80 J=280 J Answer
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