A dice is thrown 420 times and number 6 is obtained
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The probability of obtaining a six in one try is 1/6 therefore, probability of obtaining a 6 in 420 tries is 420×1/6= 70
therefore, a person may obtain 70 sizes in 420 tries of a die
therefore, a person may obtain 70 sizes in 420 tries of a die
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Thank you so much for asking this question:
Here is your answer:
We know that total number of outcomes will be n(s) = 420
And also number 6 is obtained 63 times
probability p(E)= n(E)/n(s)
= 63/420
=3/20
The percentage would be
3/20×100%
= 15%
If there is any confusion please leave a comment below.
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