Question

A dice is thrown 5 times and 6 appear 5 times. If dice is thrown again,then find the probability of not getting 6.​

Answer 1

Answer:

0 is the probability

Step-by-step explanation:

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Answer 2

Answer:0.032

Step-by-step explanation:We count the number of cases that satisfy our constraints and divide by the total number of cases to find the probability.

We first count the number of cases where we can get  3   6′s.  This number is equal to  (53).  We have  5  slots in total where we can have  6′s , and we want three slots with  6′s.   (53)=10.  

Now, we consider the other two dice. Once we have three  6′s , the other two dice can be any of the 5 numbers besides 6, so there are  5⋅5=25  different cases. Neither dice can be  6  since the question only allows  3  dice to be  6 .

25⋅10=250  total cases overall that satisfy our constraints. We multiply the two numbers together because each of the 10 different orientations of 3 6’s can be matched with  25  different ordered pairs of face values for the other two dice.

Now we calculate the total number of cases. There are 5 different dice, each with six different sides. Therefore, we have  65  total cases.

Thus, our probability is  25065=0.032,  roughly.