Math, asked by Asmit11111, 1 year ago

A dice is thrown once .Find the probability of a composite number


sbk2: 1/3
sbk2: 1/3 coz only 4 and 6 r composite numbers so probability will be N(E) /N(s) =2/6=1/3

Answers

Answered by rakshavadera
52
in a dice number 4 and 6 are composite numbers
then the favourable outcomes is 2
Probability of composite numbers = 2/6
= 1/3
Answered by wifilethbridge
23

Answer:

1/3

Step-by-step explanation:

Total outcomes on rolling a dice = {1,2,3,4,5,6} =6

Definition of Composite number:A composite number is a positive integer that can be formed by multiplying two smaller positive integers. Equivalently, it is a positive integer that has at least one divisor other than 1 and itself.

So, composite numbers on rolling a dice = {4,6} = 2

So, probability of a getting a composite number :

Total events = 6

Favorable events = {4,6} =2

So probability of a getting a composite number : \frac{2}{6} = \frac{1}{3}

Hence the probability of a composite number is 1/3

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