a dice is thrown twice and sample space is rewarded find probability of getting an even number as the sum
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So only half of 1 in 36, or 1 in 72 (1/72) will fulfill the requirements. So the chance of throwing 2 identical even dice is in this calculation 1,4%.
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Given a die is thrown twice
Total No. of possible outcomes = 6^2 =36
The possible outcomes, which are getting the even number sum
( 1,1 ) ; ( 1,3) ; (1,5) ;
(2,2) ; (2,4) ; (2,6)
(3,1) ; ( 3,3); ( 3,5)
(4,2) ; ( 4,4); ( 4,6)
( 5,1 ); ( 5,3); (5,5)
(6,2) ; ( 6,4); (6,6)
total = 18
probability of getting even number as the sum
= 18 / 36 = 1/2
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