Question

A dice is thrown twice. What is the probabilities of getting sum as 2.3,4,5,6,7,8,9,10,11,12 on each dice
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Answer 1

Answer:

Throwing a die twice and throwing two dice simultaneously are treated as the same experiment.

Sample space ={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

i) P(5 will not come up either time)= Number of times 5 does not show divided by total number of outcomes

P(5 will not come up either time)= 25

36

ii) P(5 will come up at least once)= Number of times 5 shows up at least once divided by total number of outcomes

P(5 will come up at least once)= 11

36

Answer 2

Answer:

(ii) Number of events when 5 comes at least once = 5 + 6 = 11

The required probability 11/36