A dice is thrown twice. What is the probability at least 1 of 2 throw come number 4
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11/36..................................
vishalptru587:
Can you explain setp by step
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Answer:
Step-by-step explanation:
Probability=favourable/total no. of outcomes
All outcomes=1,2,3,4,5,6,1,2,3,4,5,6
Favourable outcomes=4,4
Probability=2(4,4)divided by 12(1,2,3,4,5,6,1,2,3,4,5,6)=1/6
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