a dice is thrown what is the probability of getting a number multiply of 3 on the upper face
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1
Answer:
Total no. of outcomes; n(s) = 6 [1, 2, 3, 4, 5, 6]
No. Of favourable outcomes; n(e) = 2 [3, 6]
P(getting a multiple of 3) = n(e)/ n(s)
= 2/6 =1/3
I hope that answers the question.
Thanks.
Answered by
0
the no.s on the faces of the dice are 1,2,3,4,5,6
in these the no of multiples of three is two.
probability=no. of chances/total no.
=2/6 = 1/3
so probability=1/3
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