Math, asked by srisakthisilks2009, 1 year ago

a dice is tossed once find the probability of getting a number less than 3 a prime number a number greater than 2

Answers

Answered by Arushisin

For a no less than 3,
No. of favourable outcomes = 2
Probability = 2÷6 = 1÷3
For a prime no. ,
No. of favourable outcomes = 3
Probability = 3 ÷6 = 1÷2
For a number greater than 2,
No. of favourable outcomes = 4
Probability = 4÷6= 2÷3

srisakthisilks2009: i can not understand

Arushisin: While throwing a dice, you can get either 1,2,3,4,5 or 6. In 1st case or for a no less than 3, you can have 2 no less than 3 I.e. 1 and 2. Hence, probability will be 2÷6 = 1÷3.

Arushisin: Similarly you can understand 2nd and 3rd case also.

Answered by Dotcomputer

Hey friend, here is your answer

Outcomes when dice is thrown once = 1,2,3,4,5,6

First case
Numbers less than three= 2
Total outcomes= 6

Probability = Number of favourable outcomes/ Total number of outcomes

Probability=2/6= 1/3

Second case
Total prime numbers between 1 and 6= 3
Total numbers between 1 and 6= 6

Probability=Number of favourable outcomes/ Total number of outcomes

Probability= 3/6 = 1/2

Third case
Total numbers greater than 2 = 4
Total outcomes = 6

Probability=Number of favourable outcomes/ Total number of outcomes

Probability=4/6= 2/3

✌️ I HOPE IT HELPS. PLEASE MARK AS BRAINLIEST✌️

srisakthisilks2009: i can not understand

Dotcomputer: In the first case total outcomes when dice is thrown is either 1 or 2 or 3 or 4 or 5 or 6. So, total number of outcomes in 1st case are 6. Probability is the number of favourable outcomes / Total number of outcomes. So numbers less than 3 between 1 and 6 are 1 and 2. So probability in 1st case will be 2/6 which can be simplified and written as 1/3. This way you can understans second and third case also. HOPE YOU UNDERSTAND

srisakthisilks2009: no

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