a dice is tossed twice and the sum of the numbers appeared is found to be 6. find the conditional probability of the number 4 appearing at least once
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4 will be appear 2 times.
Total outcomes = {1+5;2+4;3+3;4+2;5+1}
Favourable outcomes = {4+2;2+4}
Hence P(4) =2/5
Total outcomes = {1+5;2+4;3+3;4+2;5+1}
Favourable outcomes = {4+2;2+4}
Hence P(4) =2/5
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