Math, asked by deepakpaswan43281, 1 year ago

A dice with three faces numbered 1 and other faces numbered 2,3,4 is thrown.What is the probability that it shows 3? Select one: a. 1/6 b. None c. 1/3 d. 1/4

Answers

Answered by amitagnidev
0

Answer:

Step-by-step explanation:

Attachments:
Answered by JeanaShupp
0

Answer: \dfrac{1}{6}

Step-by-step explanation:

Probability of having any event  = \dfrac{\text{Number of favorable outcomes}}{\text{Total outcomes}}

Given : A dice with three faces numbered 1 and other faces numbered 2,3,4 is thrown.

Total outcomes = 6

Then , the number of faces on dice has written 3 on it = 1

i.e. Number of favorable outcomes= 1

Now, the probability of getting a 3 on dice :-

=\dfrac{1}{6}

Hence, a. is the correct answer.

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