Question

A die is rolled 25 times and outcomes are recorded as under.

Outcomes 1 2 3 4 5 6
Frequency 9 4 5 6 1 0

It is thrown one more time, Find the probability of getting

a) an even number
b) a multiple of 3
c) a prime number

Answer 1

Answer:

a) $\text{P(an even number)}=\frac{2}{5}$

b) $\text{P(a multiple of 3)}=\frac{1}{5}$

c) $\text{P(a prime number)}=\frac{2}{5}$

Step-by-step explanation:

Given : A die is rolled 25 times and outcomes are recorded as under.

Outcomes 1 2 3 4 5 6

Frequency 9 4 5 6 1 0

It is thrown one more time.

To find : The probability of getting

a) an even number

b) a multiple of 3

c) a prime number

Solution :

Total number of times a die is rolled = 25

a) Even numbers are - 2,4,6

Now, probability of getting an even number is summation of the frequency of the numbers divided by total number

$\text{P(an even number)}=\frac{4+6+0}{25}$

$\text{P(an even number)}=\frac{10}{25}$

$\text{P(an even number)}=\frac{2}{5}$

b) A multiple of 3 are - 3,6

Now, probability of getting a multiple of 3 is summation of the frequency of the numbers divided by total number

$\text{P(a multiple of 3)}=\frac{5+0}{25}$

$\text{P(a multiple of 3)}=\frac{5}{25}$

$\text{P(a multiple of 3)}=\frac{1}{5}$

c) A prime number are - 2,3,5

Now, probability of getting a prime number is summation of the frequency of the numbers divided by total number

$\text{P(a prime number)}=\frac{4+5+1}{25}$

$\text{P(a prime number)}=\frac{10}{25}$

$\text{P(a prime number)}=\frac{2}{5}$

Answer 2

Answer:

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Step-by-step explanation:

Given : A die is rolled 25 times and outcomes are recorded as under.

Outcomes 1 2 3 4 5 6

Frequency 9 4 5 6 1 0

It is thrown one more time.

To find : The probability of getting

a) an even number

b) a multiple of 3

c) a prime number

Solution :

Total number of times a die is rolled = 25

a) Even numbers are - 2,4,6

Now, probability of getting an even number is summation of the frequency of the numbers divided by total number







b) A multiple of 3 are - 3,6

Now, probability of getting a multiple of 3 is summation of the frequency of the numbers divided by total number







c) A prime number are - 2,3,5

Now, probability of getting a prime number is summation of the frequency of the numbers divided by total number