Math, asked by prathikdasharath, 1 year ago

A die is rolled 300 times and following outcomes are recorded:
outcome : 1/ /2 / 3 /4 /5 /6
frequency : 42/ 60/ 55/ 53/ 60/ 30
find the probability of getting
1. more than 4
2. less than 3

Answers

Answered by kunalwadhwani
6
1.
90/300
or
3/10
2.
102/300
or
11/25

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Answered by tardymanchester
6

Answer:

\text{Probability(more than 4)}=\frac{3}{10}

\text{Probability(less than 3)}=\frac{51}{150}

Step-by-step explanation:

Given : A die is rolled 300 times and following outcomes are recorded:

Outcome :    1/  / 2  / 3   / 4   / 5   / 6

Frequency : 42/ 60/ 55/ 53/ 60/ 30

To find : The probability of getting  

1. more than 4

2. less than 3

Solution :

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

Total  number of outcome = 300

1) Probability of getting more than 4

Favorable outcome (more than 4) = 60+30=90

\text{Probability}=\frac{90}{300}

\text{Probability}=\frac{3}{10}

2) Probability of getting less than 3

Favorable outcome (less than 3) =42+60=102

\text{Probability}=\frac{102}{300}

\text{Probability}=\frac{51}{150}

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