Math, asked by pereiradian25, 4 months ago

A die is rolled. what is the probability of getting a multiple of 3 on the upper face​

Answers

Answered by SaanviTayal
0

Answer:

1/3

Step-by-step explanation:

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Answered by ImperialGladiator
4

Answer:

Probability of getting multiple of 3 on the upper surface of the die is : \sf \dfrac{1}{2}

Step-by-step explanation:

Step 1 : Express the outcomes :

Multiple of 3 in a die are : 3 & 6

Total numbers in a die are : 1, 2, 3, 4, 5, & 6

Step 2 : Calculate the required probability :

We know that,

{ \underline{ \boxed{ \sf {probablity =  \dfrac{favourable \: outcomes}{possible \: outcomes}}}}}

Where,

  • Favourable outcomes is 2 i.e., 3 & 6
  • Possible outcomes is 6.

So, probability of getting multiples of 3 in a die is :

 \sf  \to probability =  \dfrac{2}{6}  \\  \sf \to probability =  \frac{1}{3}

\therefore \bf Required \: probability = \dfrac{1}{2}

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