Question

A die is thrown 500 times and outcomes 1,2,3,4,5 and 6 with frequencies are given below in the table 1-88,2-85 ,3-76,4-75,5-86,and 6-90 find the probability of getting (a)even prime number. (b)a number greater than 4.

Answer 1

p(even prime no)=85/500=17/100=0.17
p(greater than 4)=86+90/500
=176/500
=0.252

Answer 2

Answer:

$\text{Probability(even prime number)}=\frac{17}{100}$

$\text{Probability(a number greater than 4)}=\frac{44}{125}$

Step-by-step explanation:

Given : A die is rolled 500 times and following outcomes are recorded:

Outcome :    1/  / 2  / 3   / 4   / 5   / 6

Frequency : 88/ 85/ 76/ 75/ 86/ 90

To find : The probability of getting  

1. even prime number

2. a number greater than 4

Solution :

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

Total  number of outcome = 500

1) Probability of getting even prime number

Favorable outcome (even prime number) is 2 =85

$\text{Probability}=\frac{85}{500}$

$\text{Probability}=\frac{17}{100}$

2) Probability of getting a number greater than 4

Favorable outcome (a number greater than 4) =86+90=176

$\text{Probability}=\frac{176}{500}$

$\text{Probability}=\frac{44}{125}$