Question

A die is thrown again and again until three sixes are obtained. Find the probability of third six in 6 thrown of die

Answer 1

Let the probability of obtaining a ‘six’ in a single throw of the die (p) = 1/6

Then, the probability of not obtaining a “six” in a single throw of the die (q) =1-p = 1-1/6 = 5/6

Obtaining third six in the sixth throw of the die means that in the first five throws there are 2 sixes and the third six is obtained in the sixth throw. Therefore,

Hence, probability of obtaining the third six in the sixth throw of the die is 625/23328.

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