A die is thrown at random. Find the probability of getting 1) 2. 2) a number less than 3, 3) a composite number. 4) a number not less than 4.
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A) P(e) of getting 2=1/6
B) P(e) of getting no. Less then 3= 2/6=1/3
C) p(e) of getting a comlosite no. =2/6=1/3
D) P(e) of getting no. not less then 4=2/6=1/3
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Heya dear☺❤
Total outcomes = 6
i) probability to get 2 is = 1/6
ii) probability to get no. less than 3 is= 2/6 =1/3
iii) probability to get a composite no. = 2/6 =1/3
iv) probability to get no.less than 4 = 3/6= 1/2
hope it helps❤
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