A die is thrown at random. Find the probability of getting (i)2 (ii) a number less than 3. (iii) a composite number. (iv)a number not less than 4.
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Answers
Here is your answer
✌1. Total no of outcomes = 6
The probability of getting the number 2 = 1/6
✌ 2. A number less than 3. = 1 and 2 = 2/6 = 1/3
✌ 3. A composite number = 4 and 6 = 2/6 = 1/3
✌ 4. a no not less than 4 = 4 5 and 6 = 1/2
Given,
A die is thrown.
To find,
The probability of getting (i)2 (ii) a number less than 3. (iii) a composite number. (iv)a number not less than 4.
Solution,
The required probabilities are 1/6, 1/3, 1/3, and 1/2 respectively when a die is thrown.
Total number of cases when a die is thrown = 1, 2, 3, 4, 5, 6
(1) Number of cases of getting 2 = 1
Probability = favorable cases/ Total number of cases
P ( of getting 2 ) = 1/6
(2) Number of cases of getting a number less than 3 = 1, 2
= 2
P ( of getting a number less than 3 ) = 2/6
= 1/3
(3) Number of cases of getting a composite number = 4, 6
= 2
P ( of getting a composite number ) = 2/6
= 1/3
(4) Number of cases of getting a number not less than 4 = 4, 5, 6
= 3
P ( of getting a number not less than 4) = 3/6
= 1/2
Hence, the required probabilities are 1/6, 1/3, 1/3, and 1/2 respectively when a die is thrown.