Math, asked by aaakshit18, 1 year ago

A die is thrown at random. Find the probability of getting (i)2 (ii) a number less than 3. (iii) a composite number. (iv)a number not less than 4.
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Answers

Answered by Anonymous
221
Hey !!!✌✌

Here is your answer

✌1. Total no of outcomes = 6
The probability of getting the number 2 = 1/6

✌ 2. A number less than 3. = 1 and 2 = 2/6 = 1/3

✌ 3. A composite number = 4 and 6 = 2/6 = 1/3

✌ 4. a no not less than 4 = 4 5 and 6 = 1/2
Answered by SteffiPaul
18

Given,

A die is thrown.

To find,

The probability of getting (i)2 (ii) a number less than 3. (iii) a composite number. (iv)a number not less than 4.

Solution,

The required probabilities are 1/6, 1/3, 1/3, and 1/2 respectively when a die is thrown.

Total  number of cases when a die is thrown = 1, 2, 3, 4, 5, 6

(1)   Number of cases of getting 2 = 1

                         Probability = favorable cases/ Total number of cases

      P ( of getting 2 ) = 1/6

(2)  Number of cases of getting a number less than 3 = 1, 2

                                                                                         = 2

     P ( of getting a number less than 3 ) = 2/6

                                                                  = 1/3

(3)  Number of cases of getting a composite number = 4, 6

                                                                                         = 2

    P ( of getting a composite number ) = 2/6

                                                                = 1/3

(4)   Number of cases of getting a number not less than 4 = 4, 5, 6

                                                                                                 = 3

    P ( of getting a number not less than 4) = 3/6

                                                                       = 1/2

Hence, the required probabilities are 1/6, 1/3, 1/3, and 1/2 respectively when a die is thrown.

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