Question

a die is thrown find probability of getting a 1) composite number
2) a number not less than 4​

Answer 1

Answer:

1) 1/3

2) 1/2

Step-by-step explanation:

Total number of outcomes=6

1) No. of composite number between 1 and 6 (as a die has the numbers from 1 to 6) = 2 (four and six)

Probability of getting a composite number= 2/6 = 1/3

2) No. of numbers not less than 4 between 1 and 6 = 3 (four, five and six)

Probability of getting a number not less than 4 = 3/6= 1/2

Hope it helps :)

Answer 2

S = { 1,2,3,4,5,6}

n(S) = 6

event A 1) composite no.

A= { 4,6}

n(A) =2

P(A) = n(A) / n(S)

= 2 / 6

probability of 1) = 1/3

event B 2) A no. is not less than 4

B = {4,5,6}

n(B) = 3

P(B) = n(B) /n(S)

= 3/6

probability of 2) = 1/2