a die is thrown . find the probability of getting a) prime number b) 2 or 4 c) a multiple of 2or 3
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the answer of :a)3/6=1/2
b)2/6=1/3
c)3/6=1/2
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the possible outcomes are 1,2,3,4,5,6
a) p (getting prime no.)=3/6=1/2
b)p (getting 2or 4)= 2/6=1/3
c)p (getting multiple of 2or 3)=3/6=1/2
a) p (getting prime no.)=3/6=1/2
b)p (getting 2or 4)= 2/6=1/3
c)p (getting multiple of 2or 3)=3/6=1/2
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