Question

A die is thrown. Find the probability of getting.

(i) An odd prime number.

(ii) A multiple of 3.​

Answer 1

Answer:

1.. 3/6

2 .2/6

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Answer 2

Answer:

(i) 1/3

(ii) 1/2

Step-by-step explanation:

(Probability of an Event = (Number of favourable outcomes) / (Total number of possible outcomes)

(Probability of an Event = (Number of favourable outcomes) / (Total number of possible outcomes)A dice has six possible outcomes i.e.1,2,3,4,5 and 6.

(i) The possible odd prime numbers of a dice are 3 and 5.

Therefore, number of favourable outcomes is 2 and total number of possible outcomes is 6.

Hence, probability of an odd prime number = 2/6

= 1/3 ( After reducing 2/6 in the lowest form)

(ii) The possible multiples of 3 in a dice are 3 and 6.

Therefore, number of favourable outcomes is 2 and total number of possible outcomes is 6.

Hence, probability of a multiple of 3 is = 2/6

= 1/3 ( After reducing 2/6 in the lowest form).

Hope you have understood properly.

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