A die is thrown, find the probability of the event of getting a number less than 3
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Hello
The answer is 1/3
Working : No of favourable outcomes by total no. of outcomes = 2/6=1/3
Hope this helps..
Please mark as brainliest if it does!
The answer is 1/3
Working : No of favourable outcomes by total no. of outcomes = 2/6=1/3
Hope this helps..
Please mark as brainliest if it does!
CuteIceCream:
Please mark as brainliest
Answered by
2
Pikaa ^^
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The total outcomes when a die is thrown = 6 (1,2,3,4,5,6)
Favorable outcomes ( A no. less than 3) = 2 (1 and 2)
Probability of an event can be determined by:
![\frac{No. of favorable outcomes}{Total outcomes} \frac{No. of favorable outcomes}{Total outcomes}](https://tex.z-dn.net/?f=+%5Cfrac%7BNo.+of+favorable+outcomes%7D%7BTotal+outcomes%7D+)
= ![\frac{1}{3} \frac{1}{3}](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B3%7D+)
So the probability of getting a no. less than three will be![\frac{1}{3} \frac{1}{3}](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B3%7D+)
__________________________________________________________
Pikaa ^^
____________________________________________________________
The total outcomes when a die is thrown = 6 (1,2,3,4,5,6)
Favorable outcomes ( A no. less than 3) = 2 (1 and 2)
Probability of an event can be determined by:
So the probability of getting a no. less than three will be
__________________________________________________________
Pikaa ^^
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