A die is thrown once Find probability of getting (i)a composite number, (ii)a prime number
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hey ❤
here is ur answer!!
According to the question,
A die is thrown once ,
Total number of outcomes will be = 6
Total no of prime number as a outcome = ( 2, 3, 5 ) = 3
( ii) Probability of getting a prime number =
No of possible outcomes / total number of outcomes
= 3/6
= 1/ 2
(i) total number of possible outcomes as a Composite number ( a number which is product of two postive number) = ( 4, 6) = 2
Probability of getting a composite number =
Total number of possible outcomes / total number of outcomes
=> 2/ 6
=> 1 / 3
hope it helps!!
thanks!!
here is ur answer!!
According to the question,
A die is thrown once ,
Total number of outcomes will be = 6
Total no of prime number as a outcome = ( 2, 3, 5 ) = 3
( ii) Probability of getting a prime number =
No of possible outcomes / total number of outcomes
= 3/6
= 1/ 2
(i) total number of possible outcomes as a Composite number ( a number which is product of two postive number) = ( 4, 6) = 2
Probability of getting a composite number =
Total number of possible outcomes / total number of outcomes
=> 2/ 6
=> 1 / 3
hope it helps!!
thanks!!
ayaanmalik13:
hi
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