a die is thrown once . find the probability 1 a composite no 2 a prime no
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1
Answer:
s={1,2,3,4,5,6}
p(s)=6
n(e)=p(a)/P(s)
1.a composite no:
a={4,6}
p(a)=2
n(e)=2/6=1/3
2. a prime number:
a={2,3,5}
p(a)=3
n(e)=3/6=1/2
Answered by
2
2,3,5 prime number
4,6 composite number
probality of composite number is=
2/6
probability of prime number is= 3/6
4,6 composite number
probality of composite number is=
2/6
probability of prime number is= 3/6
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