Question

A die is thrown once. Find the probability of getting (1) a composite no.s (2) a prime no.s

Answer 1

Answer:

Total outcomes [n(S)] = 6

I) Outcome of getting a composite number [n(C)] = 2

Probability [P(C)] = n(C)/n(S) = 2/6 = 1/3

ii) Outcome of getting a prime number [n(P)] = 3

Probability [P(P)] = n(P)/n(S) = 3/6 = 1/2

Hope it helps.

Answer 2

Step-by-step explanation:

S={1,2,3,4,5,6}

n(s)=6

A={,2,,4,6}

A=3

P(A)=6/3

=1/2

B={,2,3,5,}

B=3

P(B)=6/3

=1/2