Math, asked by pranaykumar31, 11 months ago

A die is thrown once. find the probability of getting (1) a composite number (2) a prime number ​

Answers

Answered by Shtakshi14
112
probability of getting a composite number =2/6=1/3

probability of getting a prime number=1/2

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Answered by tanmoyvestige
75

Answer:

1 = 1/ 2   2.   1 / 3

Step-by-step explanation:

A die is thrown once ,

Total number of outcomes will be = 6

Total no of prime number as a outcome = ( 2, 3, 5 ) = 3

( ii) Probability of getting a prime number =

No of possible outcomes / total number of outcomes

= 3/6

= 1/ 2

(i) total number of possible outcomes as a Composite number ( a number which is product of two postive number) = ( 4, 6) = 2

Probability of getting a composite number =

Total number of possible outcomes / total number of outcomes

=> 2/ 6

=> 1 / 3

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