Question

A die is thrown once . find the probability of getting 1)a composite numbers 2)a prime numbers​

Answer 1

Answer:

Step-by-step explanation:

P(a composite number) = 3/6 = 1/2

P(a prime number) = 3/6 = 1/2

Answer 2

lets first count composite numbers

4and 6 =) 2

now lets count prime numbers

2,3and 5 =) 3

(we r not taking 1 as its not a prime number not a composite number)

1) so total chances =) 6

favourable chances =) 2

probablity = favourable chances/total chances

=) 2/6

1/3 are chances of coming a composite number

2)now total chances =6

favourable chances =3

now, probality= 3/6

=1/2

the probablity of coming is a prime number is 1/2

hope this helps u mate