Math, asked by gagansanotra32, 6 months ago

A die is thrown once Find the probability of getting (1) An even Number (2) An odd number (3) A number greater than 3​

Answers

Answered by khushboo2309
0

Answer:

1. 1/2

2.1/2

3.1/2

Step-by-step explanation:

1. there are 3 even no from 1 to 6

2. there are 3 odd no from 1 to 6

3. there are 3 no greater than 3 from 1 to 6

Answered by Anonymous
9

Answer:

To find the probability of an event, we use the following formula:-

\dfrac{Number\:of\:favourable\:outcomes}{Total\:number\:of\:outcomes\:possible}

Now let's solve all the parts using this formula!

Note that, total number of outcomes = 6

1) Number of even numbers in a die = 3

  Probability of getting an even number = 3/6 = 1/2

2) Number of odd numbers in a die = 3

   Probability of getting an odd number = 3/6 = 1/2

   

3) Number of numbers greater than 3 = 3

   Probability of getting a number greater than 3 = 3/6 = 1/2

The answer of all parts is 1/2.

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