Question

A die is thrown once. Find the probability of getting a number greater then 7​

Answer 1

Answer:

its probability is zero. Because die does not contain more than 6 numbers and they are 1,2,3,4,5,6.

Answer 2

The probability of getting a number greater than 7 is 0

Given :

A die is thrown once

To find :

The probability of getting a number greater than 7

Solution :

Step 1 of 3 :

Find total number of possible outcomes

Here it is given that a die is thrown once

The possible outcomes are 1 , 2 , 3 , 4 , 5 , 6

∴ Total number of possible outcomes = 6

Step 2 of 3 :

Find number of possible outcomes for the event

Let A be the event that of getting a number greater than 7

Since a die is thrown once

So outcomes will be one of 1 , 2 , 3 , 4 , 5 , 6. A number greater than 7 can not occurs

So total number of possible outcomes for the event A = 0

Step 3 of 3 :

Find the probability of the event

The probability of getting a number greater than 7

= P(A)

$\displaystyle \sf{ = \frac{Number \: of \: favourable \: cases \: to \: the \: event \: A }{Total \: number \: of \: possible \: outcomes }}$

$\displaystyle \sf = \frac{0}{6}$

$= 0$

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