Question

a die is thrown once. find the probability of getting a number which has atleast 2 factors

Answer 1

Answer:

P = 5/6

Step-by-step explanation:

There are 6 numbers on a die.

foactors of each numbers

1  -  1

2 -  1 , 2

3 -  1 , 3

4 -  1, 2, 4

5 -  1, 5

6 - 1, 2, 3, 6

Thus number with atleast two factors are - 2, 3, 4, 5, 6

i.e. - Total Numbers with atleast two factors = 5

To find probability - for a single throw

P = Total number with atleast 2 factors / Total numbers

P = 5 / 6

Answer 2

Answer:

Answer:5/6

Step-by-step explanation:

No of possible outcomes = 6

No of outcomes with atleast 2 factors(2,3,4,5,6) = 5

Therefore, Probability of Event = 5/6