A die is thrown once . Find the probability of getting at most 2
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if the die thrown once .then the outcomes will 6 as 1,2,3,4,5,6
so, the probability of geting at most 2 =2/6 =1/3
so, the probability of geting at most 2 =2/6 =1/3
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n(S)=6
n(E)=1+1=2(1,2)
P(E)=n(E)/n(S)=2/6=1/3
n(E)=1+1=2(1,2)
P(E)=n(E)/n(S)=2/6=1/3
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