Question

A die is thrown once. Find the probability of getting (i) a prime number; (ii) a number lying between 2 and 6; (iii) an odd number.​

Answer 1

Answer:

Number of outcomes on throwing a die is (1, 2, 3, 4, 5, 6) = 6

Number of prime numbers on dice are 1, 3 and 5 = 3

(i) Probability of getting a prime number = Number of prime numbers/total number of outcomes

= 3/6 = 1/2

(ii) Numbers lying between 2 and 6 are 3, 4, 5 = 3

Probability of getting a number lying between 2 and 6 = Number lying between 2 and 6/total number of outcomes

= 3/6 = 1/2

(iii) Total number of odd numbers are 1, 3 and 5=3

Probability of getting a odd number = Number of odd numbers/total number of outcomes

= 3/6 = 1/2