Question

A die is thrown once. Find the probability of getting (i) a prime number; (ii) a number lying between 2 and 6; (iii) an odd number.

Answer 1

total no of outcomes = 6 

S= {1 , 2, 3, 4, 5, 6}

no of prime no = 3 {2 ,3 ,5 }

P(prime no ) = favorable outcome
                           total outcome

= 3/6

=1/2
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P(no lying between 2 and 6 )

{3 ,4, 5 }

= favorable outcome
        total outcome

= 3/6  
= 1/2
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P(odd no ) 
{1 , 3 , 5 )

= favorable outcome
        total outcome
=3/6

=1/2