Math, asked by prathameshv092, 5 months ago

A die is thrown once. Find the probability to getting
I)A prime number
ii)An even number
iii)An odd number​

Answers

Answered by nandhu130
2

Step-by-step explanation:

Dice come in a variety of sizes, with a variety of numbering systems used on them.

The traditional die you may be thinking of has six faces, and is numbered 1 2 3 4 5 6, each digit one time.

The chances of getting a number that fits one of the three types depends on the type in question.

There are 6 faces on the die, and of those, 2, 3, and 5 are prime, resulting in a 3/6 chance of such a roll.

On the same die, there are three odd numbers, 1, 3 and 5, resulting in a 3/6 chance of such a roll

On the same die, there are three even numbers, 2, 4, and 6, again resulting in a 3/6 chance of such a roll.

You may get a number which is both prime and odd. This is true of 3 and 5, or 2/6

You may get a number which is both prime and even. This is true of 2, or 1/6

These latter two facts don’t improve the chances of getting a prime number nor of getting an even number nor of getting an odd number. It’s just an interesting aside, you COULD get two at once. But there are only 3 such results, 2, 3 and 5, and so the odds of getting two at once are still only 3/6

But that’s not the question you asked. Given the numbers 1 2 3 4 5 6 on a fair die…Of those digits you have NO chance of getting a number that is even, odd, and prime, because no such number exists. I cheated, it doesn’t matter what size die you use, because there actually is no such number.

D4, D8, D10, D20, D34, D100, it really doesn’t matter, because a number which is unobtanium will never be rolled.

For a die with any number of faces n, the chance of rolling an even, odd, and prime number in a single roll is 0/n.

Answered by mishrasweta1947
7

ANSWER

Total outcomes that can occur are 1,2,3,4,5,6

Number of possible outcomes of a dice=6

3) Numbers which are odd=1,3,5

Total numbers which are odd=3

Probability of getting an odd number

=(Number of outcomes where there is an odd)÷(Total number of outcomes)

=

3/6=1/2

2) similarly

even no. =2,4,6

total no. =6

probability getting an even no.

3/6=1/2

1) similarly

prime no. =1,3,5

total no. =6

probability getting a prime number

3/6=1/2

I hope it's help you!!!

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