A die is thrown once. The probability of getting an even number and a multiple of 3 is
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Given that the die is thrown once.
Possible outcomes = 6^1
= 6.
The probability of getting an even number = {2,4,6}
= 3.
Note: We cannot get an even number which is multiple of 3 when a single die is thrown.
The probability of getting an even number or a multiple of 3 = {2,3,4,6}
= 4.
Therefore the required probability = 4/6
= 2/3.
Hope this helps!
Possible outcomes = 6^1
= 6.
The probability of getting an even number = {2,4,6}
= 3.
Note: We cannot get an even number which is multiple of 3 when a single die is thrown.
The probability of getting an even number or a multiple of 3 = {2,3,4,6}
= 4.
Therefore the required probability = 4/6
= 2/3.
Hope this helps!
siddhartharao77:
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4
Answer:
2/3 is correct answer
Step-by-step explanation:
please thanks to my answer
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