Question

A die is thrown once. The probability of getting an even number and a multiple of 3 is

Answer 1

Given that the die is thrown once. 

Possible outcomes = 6^1

                                  = 6.


The probability of getting an even number = {2,4,6}

                                                                         = 3.


Note: We cannot get an even number which is multiple of 3 when a single die is thrown.


The probability of getting an even number or a multiple of 3 = {2,3,4,6}

                                                                                                      = 4.




Therefore the required probability = 4/6

                                                           = 2/3.


Hope this helps!

Answer 2

Answer:

2/3 is correct answer

Step-by-step explanation:

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