Question

a die is thrown once what is the probability of getting (1) the number 4 (2) and odd number

Answer 1

Heya!!!


Answer to your question:

P (E)= No. of favourable outcomes/ Total no. of outcomes..

Total no. of outcomes in each case=6

1) Favourable outcomes=1 (4)
P (E)= 1/6

2)Favourable outcomes=3 (1,3,5)
P (E)=3/6=1/2

Hope it helps ^_^

Answer 2

(i)
A = { the number 4 }
A = {4}

n(A) = 1 ; n(S) = 6

p(A) = n(A)/n(S) = 1/6

(ii)
B = { an odd number }
B = { 1,3,5 }

n(B) = 3 ; n(S) = 6

p(B) = n(B)/n(S) = 3/6 (or) 1/2

#Hassan