Question

a die is thrown once what is the probability of getting number>= 2​

Answer 1

Answer:

5/6

Step-by-step explanation:

No of total possible outcomes=6 {1,2,3,4,5,6}

P(of getting no greater than 2)=5/6 {2,3,4,5,6}

Answer 2

Answer:

the probability of getting number >= 2 when a die is thrown once is   $\frac{5}{6}$

Step-by-step explanation:

sample space  = {1,2,3,4,5,6}

n(s) = 6

Let A be the probability of getting number >= 2

A = {2,3,4,5,6}

n(A) = 5

p(A) = $\frac{n(A)}{n(s)}$

       = $\frac{5}{6}$

Therefore, the probability of getting number >= 2 when a die is thrown once is   $\frac{5}{6}$