A die is thrown once .What is the probability of getting a prime number
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Answer:
1/2
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No. of prime no.s =3 (2,3,5)
Total no. of outcomes =6 (1,2,3,4,5,6)
Let P(E) be any event that we get a prime no. on throwing a dice
P(E)= No. of favourable outcomes/ Total no. of outcomes
=> 3/6
=>½
:•P(E) = ½
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