find three different solutions of the each of the following equations x+y=0
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Given equation is x + y = 0
y = - x
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x | y = -x | ( x , y )
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0 | y = 0 | ( 0 , 0 )
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1 | y = -1 | ( 1 , - 1 )
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4 | y = -4 | ( 4 , -4 )
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Therefore ,
( 0 , 0 ) , ( 1 , -1 ) and ( 4 , -4 ) are
three solutions of x + y = 0
Answered by
1
Answer:
x= -1
y=+1
x+y=(-1+1)=0
x= -2
y=+2
x+y=(-2+2)=0
x= -3
y=+3
x+y=(-3+3)=0
There fore (-1,1),(-2,2),(-3,3) are three different solutions of the equation x+y=0
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