Math, asked by srerhari2, 2 months ago

A die is thrown once. What is the probability of getting a prime number, even number & odd number?

Answers

Answered by Swaroopboi
1

Answer:

prime no. 1/2

even no. 1/2

odd no. 1/2

Answered by Anonymous
10

Step-by-step explanation:

Numbers in the dice : 1, 2, 3, 4, 5 & 6.

n ( S ) = 6

( i ) The probability of getting a prime number.

Let A be the probability of getting a prime number in the dice.

A = { 2, 3, 5 }

n ( A ) = 3

P ( A ) = n ( A ) / n ( S )

= 3 / 6

P ( A ) = 1 / 2

Therefore, the probability of getting a prime number is

1 / 2.

( ii ) The probability of getting a even number.

Let B be the probability of getting a even number in the dice.

B = { 2, 4, 6 }

n ( B ) = 3

P ( B ) = n ( B ) / n ( S )

= 3 / 6

P ( B ) = 1 / 2

Therefore, the probability of getting a even number is

1 / 2.

( iii ) The probability of getting a odd number.

Let C be the probability of getting a odd number in the dice.

C = { 1, 3, 5 }

n ( C ) = 3

P ( C ) = n ( C ) / n ( S )

= 3 / 6

P ( C ) = 1 / 2

Therefore, the probability of getting a odd number is

1 / 2.

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