A die is thrown once. What is the probability of getting a prime number?
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Answered by
5
SOLUTION :
Given : A die is thrown once .
A die has 6 faces marked as 1, 2, 3, 4, 5 and 6.
If we throw one die then there possible outcomes are as follows: 1, 2, 3, 4, 5 and 6
Number of possible outcomes are = 6
Let E = Event of getting a prime number
Prime number on a die are : 2, 3, 5
Number of outcome favourable to E = 3
Probability (E) = Number of favourable outcomes / Total number of outcomes
P(E) = 3/6 = 1/2
Hence, the required probability of getting a prime number , P(E) = 1/2
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Answered by
4
Total number of elementary events=6
Number of favourable elementary events=2,3,5
=3
So, probability=3/6
=1/2
Number of favourable elementary events=2,3,5
=3
So, probability=3/6
=1/2
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