Question

A die is thrown once. What is the probability of getting a prime number?

Answer 1

SOLUTION :  

Given : A die is thrown once .

A die has 6 faces marked as 1, 2, 3, 4, 5 and 6.

If we throw one die then there possible outcomes are as follows: 1, 2, 3, 4, 5 and 6

Number of possible outcomes are = 6

Let E = Event of getting a prime number

Prime number on a die are : 2, 3, 5  

Number of outcome favourable to E = 3

Probability (E) = Number of favourable outcomes / Total number of outcomes

P(E) = 3/6  = 1/2

Hence, the required probability of getting a  prime number , P(E) = 1/2

HOPE THIS ANSWER WILL HELP  YOU…

Answer 2

Total number of elementary events=6

Number of favourable elementary events=2,3,5
=3

So, probability=3/6

=1/2