Question

If Cos theta=m/n find the values of cot theta and cosec theta

Answer 1

Hope it will be correct

Answer 2

Answer:

Cos theta = B\H = m/n

Hence, B=m and H=n

cot theta = B/P = B is given, but we have to find P. By pythagoras theorem.

B^2 = H^2 = p^2

m^2 = n^2 = p^2

p = root m^2 - n^2

Hence,

Cot theta = B/P = m/root m^2 - n^2

Cosec theta =H/P = n/root m^2 - n^2

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