Question

a die is thrown once what is the probability of getting (i)a cube number (ii) even number
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Answer 1

Answer:

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Answer 2

Answer:

S={1,2,3,4,5,6}

n(S)= 6

now,

(i) a cube number

set of cube numbers

=C

={1}

number of elements

=n(C)

=1

now,,

probability of getting a cube number

=p(C)

$= \frac{n(c)}{n(s)} \\ = \frac{1}{6}$

(ii) an even number

set of even number

=E

={2,4,6}

number of elements

=n(E)

=3

probability of even number

=p(E)

$= \frac{n(e)}{n(s)} \\ = \frac{3}{6} \\ = \frac{1}{2}$