Math, asked by its567818, 3 months ago

A die is thrown,then find the probability of the following events
1.A is event getting a number divisible by 3
2.B is event getting a number less than 5​

Answers

Answered by aarushisaxenaedu
0

Step-by-step explanation:

Total possible outcomes = 6 (6 numbers in a die)

1. Case A

Number of favourable outcomes = 2 (3 and 6 are divisible by 3)

So probability = No. of favourable outcomes / total possible outcomes

= 2/6 = 1/3

2. Case B

No. of favourable outcomes = 4 (1,2,3 & 4 are smaller than 5)

So probability = No. of favourable outcomes / total possible outcomes

= 4/6 = 2/3

Answered by akelkar365
0

Answer:

Itzz simple

Easy Pesy.

Step-by-step explanation:

Total possible outcomes = 6 (6 numbers in a die)

1. Case A

Number of favourable outcomes = 2 (3 and 6 are divisible by 3)

So probability = No. of favourable outcomes / total possible outcomes

= 2/6 = 1/3

Similar questions