A die is thrown twice. the probability that at least one of the two throws comes up with the number 3 is:
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DICE is thrown twice. total possibilities= 36
we want at least one 5 i.e we can have one of the dice showing 5 or both dice showing 5.
both dice showing - there is only one way i.e.(5,5)
let first die shows 5 then the second die can take 1 or 2 or 3 or 4 or 6 in five ways
namely (5,1) (5,2) (5,3) (5,4) (5,6)
now suppose second die shows 5 then the first die can take 1 or 2 or 3 or 4 or 6 in five ways namely (1,5) (2,5) (3,5) (4,5) (6,5)
so total desired possibility is 1+5+5=11
so prob is 11/36
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Answer:
Total possibility is 11/36
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