Question

a die is thrown twice. what is the probability of the events (getting a doublet)

Answer 1

HERE IS YOUR ANSWER....

IF YOU HAVE ANY DOUBTS ASK ME.....

HOPE IT HELPS YOU

Answer 2

Answer:

$\text{Probability}=\frac{1}{6}$

Step-by-step explanation:

Given : A die is thrown twice.

To find : The probability of the events (getting a doublet)

Solution :  

When two dice rolled once the outcome will be,

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)  

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)  

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)  

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)  

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)  

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)  

Now,  

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

The probability of the events (getting a doublet)

Favorable outcome are :  (1,1) ,(2,2), (3,3), (4,4), (5,5), (6,6)

So, Favorable outcome = 6

Total number of outcome = 36

$\text{Probability}=\frac{6}{36}$

$\text{Probability}=\frac{1}{6}$