Question

a die is thrown twice what is the probability that 5 will not correct up either time be 5 will come up at least once​

Answer 1

Answer:

1/6, or 5/6

Step-by-step explanation:

A die has 6 sides, giving 6 possible chances. NOT throwing a 5 results in a 1/6 chance; but if the answer was reversed, it would be a 5/6 chance of rolling a number APART from 5.

Because we are rolling it again, it would give us 12 possible chances. To not roll a 5 would be 2/12. That can be simplified to 1/6. And again; if the answer was reversed, it would be 10/12 chance of rolling a number apart from 5. 10/12 can be simplified to 5/6.

Hope this helps

Answer 2

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Outcomes are:

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

So, the total number of outcome = 6 × 6 = 36

Method 1:

Consider the following events.

A = 5 comes in the first throw,

B = 5 comes in second throw

P(A) = 6/36,

P(B) = 6/36 and

P(not B) = 5/6

So, P(notA) = 1 – 6/36 = 5/6

∴ The required probability = 5/6 × 5/6 = 25/36

Method 2:

Let E be the event in which 5 does not come up either time.

So, the favourable outcomes are [36 – (5 + 6)] = 25

∴ P(E) = 25/36

• Number of events when 5 comes at least once = 11 (5 + 6)

∴ The required probability = 11/36

Hope it's Helpful.....:)