Question

A die is thrown twice. What is the probability that (i) 5 will not come up either time? (ii) 5 will come up at least once?

Answer 1

there are 36 outcomes in which 25 of them 5 will not come up either times so the probability of part 1 is 25/36
in this 1 outcome in which 5 will occur on both dice and 10 uotcomes in which 5 will occur on one of the dice so the probability is
(1+10)/36=11/36

Answer 2

Answer:

Total event =6×6 =36

Events of getting 5 are = (5,1),( 5,2),( 5,3),( 5,4),( 5,5),( 5,6),(1,5),(2,5),(3,5), (4,5),( 6,5)

probability of getting getting 5 =11/36

Probability of not getting 5 =1-(11/36) =25/36

probability of getting. 5 exactly one time is =10/36

Step-by-step explanation: