A die is thrown up, find the probability of:
(i) getting a number less than 7
(ii) getting a number more than 6
(iii) getting a non-even prime number
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i) Number of possible outcomes = 6
Total number of outcomes = 6
•°• P(E) = 6/6 = 1 - Sure Evenet.
ii) Number of possible outcomes = 0
Total number of outcomes = 6
•°• P(E) = 0 /6 = 0 - Impossible event.
iii) Total number of possible outcomes = 2
Total number of outcomes = 6
•°• P(E) = 2/6 = 1/3
Brainliest pls xD
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