Question

A die is thrown up, find the probability of:
(i) getting a number less than 7
(ii) getting a number more than 6
(iii) getting a non-even prime number​

Answer 1

Answer:

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Answer 2

i) Number of possible outcomes = 6

Total number of outcomes = 6

•°• P(E) = 6/6 = 1 - Sure Evenet.

ii) Number of possible outcomes = 0

Total number of outcomes = 6

•°• P(E) = 0 /6 = 0 - Impossible event.

iii) Total number of possible outcomes = 2

Total number of outcomes = 6

•°• P(E) = 2/6 = 1/3

Brainliest pls xD